Industry-Knowledge

brake horsepower formula for centrifugal pump

The brake horsepower (BHP) of a centrifugal pump is the actual power required to drive the pump and move the fluid, accounting for efficiency losses. The formula for brake horsepower is:

Brake Horsepower (BHP) Formula:

BHP=Q×H×ρ×g3960×ηpBHP=3960×ηpQ×H×ρ×g

Where:

  • BHP = Brake horsepower (HP)

  • Q = Flow rate (gallons per minute, GPM)

  • H = Total head (feet, ft)

  • ρ (rho) = Fluid density (pounds per gallon, lb/gal; water ≈ 8.34 lb/gal)

  • g = Gravitational acceleration (implicit in the constant 3960)

  • η_p (eta_p) = Pump efficiency (decimal, e.g., 0.85 for 85% efficiency)

Simplified Formula (for water at standard conditions):

Since ρ × g is constant for water (≈ 8.34 lb/gal), the formula reduces to:

BHP=Q×H3960×ηpBHP=3960×ηpQ×H

Alternative Formula (in SI Units: kW):

BHP (kW)=Q×H×ρ×g1000×ηpBHP (kW)=1000×ηpQ×H×ρ×g

Where:

  • Q = Flow rate (m³/s)

  • H = Head (meters, m)

  • ρ = Density (kg/m³; water ≈ 1000 kg/m³)

  • g = 9.81 m/s²

  • η_p = Pump efficiency

Key Notes:

  1. 3960 Constant: Derived from converting (ft·lb/min) to horsepower (1 HP = 550 ft·lb/s = 33,000 ft·lb/min).

  2. Efficiency (η_p): Typically ranges from 50% to 90% depending on pump design and operating conditions.

  3. Density Adjustment: For fluids other than water, multiply by specific gravity (SG = ρ_fluid / ρ_water).

Example Calculation (US Units):

  • Flow (Q) = 500 GPM

  • Head (H) = 100 ft

  • Efficiency (η_p) = 80% (0.8)

  • Fluid = Water (ρ = 8.34 lb/gal)

BHP=500×1003960×0.8=50,000316815.8 HPBHP=3960×0.8500×100=316850,000≈15.8 HP

Conclusion:

Brake horsepower increases with higher flow, head, or fluid density, and decreases with better pump efficiency. Always verify pump curves for real-world performance.

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